A) \[\ell +m=2\]
B) \[3\ell +m=4\]
C) \[3\ell -m=2\]
D) AII of these
Correct Answer: D
Solution :
| If \[5x\ge 15\] i.e. \[x\ge 3,\] then \[{{x}^{2}}-6x-5x+15-5=0\] i.e. \[{{x}^{2}}-11x+10=0\] i.e. \[x=1,\]10 |
| \[\therefore \] \[x=10\] is a solution |
| If \[5x<15\] i.e. \[x>3,\] then |
| \[{{x}^{2}}-6x+5x-15-5=0\] |
| i.e. \[{{x}^{2}}-x-20=0\] |
| i.e. \[x=5,\,\,-\,4\] |
| \[\therefore \] \[x=-\,4\]is a solution |
| Thus \[\ell =1,\] \[m=1\] |
You need to login to perform this action.
You will be redirected in
3 sec
