A) \[N{{H}_{4}}N{{O}_{3}}\And {{N}_{2}}O\]
B) \[N{{H}_{4}}N{{O}_{2}}\And {{N}_{2}}\]
C) \[HN{{O}_{3}}\And {{O}_{2}}\]
D) \[{{N}_{2}}O\And {{H}_{2}}O\]
Correct Answer: A
Solution :
\[{{\operatorname{NH}}_{4}}Cl{{O}_{4}}+HN{{O}_{3}}\to HCl{{O}_{4}}+N{{H}_{4}}N{{O}_{3}}\] \[{{\operatorname{NH}}_{4}}N{{H}_{3}}\xrightarrow{\Delta }{{N}_{2}}O+2{{H}_{2}}O\]
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