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KVPY Sample Paper KVPY Stream-SX Model Paper-10

  • question_answer
    The electro negativities of four atoms labeled as D, E, F and G are as follows. D=3.8, E=3.3, F=2.8 and G=1.3. if  the atoms from the molecules DE, DG, EG and DF, the order of arrangement of these molecules in the increasing order of covalent bond character is

    A) \[DG<EG<DF<DE\]

    B) \[DF<DG<DE<EG\]

    C) \[DG<DF<EG<DE\]  

    D) \[DE<EG<DG<DF\]

    Correct Answer: A

    Solution :

    Compound having maximum electronegativity difference is more ionic. Hence the correct order is \[\operatorname{DG}<EG<DF<DE\]


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