A) \[\frac{1}{e},\]\[{{e}^{-1/e}}\]
B) e, \[{{e}^{1/e}}\]
C) \[\frac{1}{e},\]
D) none of these
Correct Answer: A
Solution :
\[f\,(x)={{x}^{x}}\] |
\[f'(x)={{x}^{x}}(1+\ln x)=0\] \[\Rightarrow \] \[x=\frac{1}{e}\] |
\[\therefore \] \[a=\frac{1}{e}\] & \[b={{e}^{-\,\frac{1}{e}}}\] |
You need to login to perform this action.
You will be redirected in
3 sec