A) \[h\]
B) \[{{h}^{2}}\]
C) \[{{h}^{-\,2}}\]
D) \[{{h}^{0}}\]
Correct Answer: D
Solution :
Let P luminous intensity of source, then amount of light diverging from source in 1 s is \[4\pi P.\] |
Light escapes in air through a cone of semi-vertical angle \[{{i}_{c}},\] |
So, fraction of light that escapes in the air is |
\[f=\frac{2\pi P(1-\cos {{i}_{c}})}{4\pi P}=\frac{1}{2}(1-\cos {{i}_{c}})\] |
\[=\frac{1}{2}(1-\sqrt{1-{{\sin }^{2}}{{i}_{c}})}\] |
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