A) \[A=N{{a}_{2}}Cr{{O}_{4}};\] \[B=N{{a}_{2}}C{{r}_{2}}{{O}_{7}};\] \[C=N{{a}_{2}}Cr{{O}_{4}};\] \[D=A{{g}_{2}}Cr{{O}_{4}}\]
B) \[A=N{{a}_{2}}Cr{{O}_{4}};\] \[B=N{{a}_{2}}C{{r}_{2}}{{O}_{7}};\] \[C=N{{a}_{2}}C{{r}_{2}}{{O}_{7}};\] \[D=A{{g}_{2}}C{{r}_{2}}{{O}_{7}};\]
C) \[A=N{{a}_{2}}C{{r}_{2}}{{O}_{7}};\] \[B=N{{a}_{2}}Cr{{O}_{4}};\] \[C=N{{a}_{2}}C{{r}_{2}}{{O}_{7}};\] \[D=A{{g}_{2}}C{{r}_{2}}{{O}_{7}}\]
D) \[A=C=N{{a}_{2}}Cr{{O}_{4}};\] \[B=N{{a}_{2}}C{{r}_{2}}{{O}_{7}};\] \[D=A{{g}_{2}}C{{r}_{2}}{{O}_{7}}\]
Correct Answer: A
Solution :
| \[Cr{{O}_{2}}C{{l}_{2}}+4NaOH\xrightarrow{{}}N{{a}_{2}}Cr{{O}_{4}}(A)\]\[+2NaCl+2{{H}_{2}}O\] |
| \[N{{a}_{2}}Cr{{O}_{4}}+{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}N{{a}_{2}}C{{r}_{2}}{{O}_{7}}(B)+N{{a}_{2}}S{{O}_{4}}\]\[+{{H}_{2}}O\] |
| \[N{{a}_{2}}C{{r}_{2}}{{O}_{7}}+NaOH\xrightarrow{{}}N{{a}_{2}}Cr{{O}_{4}}(C)+{{H}_{2}}O\] |
| \[N{{a}_{2}}Cr{{O}_{4}}+2AgN{{O}_{3}}\xrightarrow{{}}A{{g}_{2}}Cr{{O}_{4}}(D)\]\[+2NaN{{O}_{3}}\] |
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