| The reverse breakdown voltage of a Zener diode is 5.6 V in the given circuit. The current I. through the Zener is: |
 |
A) 7 mA
B) 10 mA
C) 17 mA
D) 15 mA
Correct Answer: B
Solution :
\[{{i}_{z}}=\frac{3.4}{200}-\frac{5.6}{800}=10\,MA.\]
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