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KVPY Sample Paper KVPY Stream-SX Model Paper-12

  • question_answer
    An alternating voltage \[v(t)=220\,\sin \,100\pi t\]volt is applied to a purely resistive load of \[50\,\,\Omega .\] The time taken for the current to rise from half of the peak value to the peak value is:

    A) 5 ms

    B) 7.2 ms

    C) 3.3 ms

    D) 2.2 ms

    Correct Answer: C

    Solution :

    \[\Delta \phi =\frac{\pi }{3}=(100\pi )\Delta t\] \[\Rightarrow \]   \[\Delta t=\frac{{{10}^{3}}}{300}ms=3.3ms.\]


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