A) \[n=2\to n=5\]
B) \[n=2\to n=3\]
C) \[n=1\to n=4\]
D) \[n=2\to n=4\]
Correct Answer: D
Solution :
For H \[\Delta E=Rhc\left[ 1-\frac{1}{4} \right]=\frac{3Rhc}{4}\] For He \[(1\to 4)\Delta E=Rhc\left( 1-\frac{1}{16} \right)4=\frac{15}{4}Rhc\] \[(2\to 4)\Delta E=Rhc\left( \frac{1}{4}-\frac{1}{16} \right)4=\frac{3}{4}Rhc.\]
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