question_answer

Two particles move at right angle to each other. Their de-Broglie wavelengths are\[{{\lambda }_{1}}\]and \[{{\lambda }_{2}}\] respectively. The particles suffer perfectly inelastic collision. The de-Broglie wavelength \[\lambda ,\]of the final particle, is given by:

A) \[\lambda =\frac{{{\lambda }_{1}}+{{\lambda }_{2}}}{2}\]

B) \[\frac{1}{{{\lambda }^{2}}}=\frac{1}{\lambda _{1}^{2}}+\frac{1}{\lambda _{2}^{2}}\]

C) \[\frac{2}{\lambda }=\frac{1}{{{\lambda }_{1}}}+\frac{1}{{{\lambda }_{2}}}\]           

D) \[\lambda =\sqrt{{{\lambda }_{1}}{{\lambda }_{2}}}\]