A) \[A{{T}^{-\,3}}M{{L}^{\text{3/2}}}\]
B) \[{{A}^{-\,1}}TM{{L}^{3}}\]
C) \[A{{T}^{2}}{{M}^{-\,1}}{{L}^{-1}}\]
D) \[{{A}^{2}}{{T}^{3}}{{M}^{-\,1}}{{L}^{-\,2}}\]
Correct Answer: D
Solution :
\[{{\in }_{0}}={{M}^{-1}}{{A}^{2}}{{L}^{-3}}{{T}^{4}}\] \[{{\mu }_{0}}=ML{{T}^{-2}}{{A}^{-2}}\] \[\sqrt{\frac{{{\in }_{0}}}{{{\mu }_{0}}}}={{[{{M}^{-2}}{{A}^{2}}{{L}^{-4}}{{T}^{6}}]}^{1/2}}\] \[=\,{{M}^{-1}}{{A}^{2}}{{L}^{-2}}{{T}^{3}}.\]
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