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KVPY Sample Paper KVPY Stream-SX Model Paper-12

  • question_answer
    The bob of a simple pendulum has mass 2g and charge of \[5.0\mu C.\] It is at rest in a uniform horizontal electric field of intensity 2000 V/m. At equilibrium, the angle that the pendulum makes with the vertical \[(take\,\,g=10\text{m/}{{\text{s}}^{2}})\]

    A) \[{{\tan }^{-\,1}}(5.0)\]

    B) \[{{\tan }^{-\,1}}(0.5)\]

    C) \[{{\tan }^{-\,1}}(0.2)\]

    D) \[{{\tan }^{-\,1}}(0.2)\]

    Correct Answer: B

    Solution :

    \[\tan \theta =\frac{qE}{Mg}=\frac{5\times {{10}^{-6}}\times 2\times {{10}^{3}}}{2\times {{10}^{-3}}\times 10}=\frac{1}{2}\] \[\Rightarrow \]   \[\theta ={{\tan }^{-1}}\left( \frac{1}{2} \right).\]


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