A) \[{{10}^{8}}m/s\]
B) \[2.4\times {{10}^{8}}m/s\]
C) \[12\times {{10}^{8}}m/s\]
D) \[3\times \text{1}{{\text{0}}^{\text{8}}}m/s\]
Correct Answer: B
Solution :
\[{{R}^{2}}=9+{{(R=0.5)}^{2}}\] |
\[R=9.25\,\,cm\] |
\[\frac{1}{37}=(\mu -1)\left( \frac{1}{\infty }+\frac{1}{R} \right)\] |
\[\Rightarrow \mu =1.25=\frac{c}{v}\] |
\[v=\frac{3\times {{10}^{8}}}{1.25}=2.4\times {{10}^{8}}m/s\] |
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