| In the given LC circuit if initially capacitor C has charge Q on it and 2C has charge 2Q. Then after closing switch S at \[t=0\] |
 |
A) Energy will get equally distributed in both the capacitor
B) Initial rate of growth of current in indicator will be \[2Q/3CL\]
C) Maximum energy in the inductor will \[3{{Q}^{2}}/2C\]
D) None of these
Correct Answer: C
Solution :
Maximum energy in the inductor will be \[3{{Q}^{2}}/2C\]
You need to login to perform this action.
You will be redirected in
3 sec
