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KVPY Sample Paper KVPY Stream-SX Model Paper-13

  • question_answer
    The path difference between two interfering waves at a point on the screen is \[\lambda /6.\] The ratio of intensity at this point and that at the central bright fringe will be \[-\] (Assume that intensity due to each slit in same)

    A) 0.853

    B) 8.53

    C) 0.75     

    D) 7.5

    Correct Answer: C

    Solution :

    At path difference \[\frac{\lambda }{6},\]phase difference is \[\frac{\pi }{3}\] \[I={{I}_{0}}+{{I}_{0}}+2{{I}_{0}}\cos \frac{\pi }{3}=3\,{{I}_{0}}\] \[{{I}_{\max }}=4{{I}_{0}}\] So the required ratio is \[\frac{3{{I}_{0}}}{4{{I}_{0}}}=0.75\]


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