A) \[\text{Sr(N}{{\text{O}}_{\text{3}}}{{\text{)}}_{\text{2}}}\]
B) \[\text{Mg(N}{{\text{O}}_{\text{3}}}{{\text{)}}_{\text{2}}}\]
C) \[\text{Ca(N}{{\text{O}}_{\text{3}}}{{\text{)}}_{\text{2}}}\]
D) \[\text{Ba(N}{{\text{O}}_{\text{3}}}{{\text{)}}_{\text{2}}}\]
Correct Answer: D
Solution :
Smaller in size of center atoms more water molecules will crystallize, hence, Ba \[{{(\text{N}{{\text{O}}_{3}})}_{2}}\]is answer due to its largest size of +ve ion.
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