A) 420
B) 392
C) 361
D) 360
Correct Answer: C
Solution :
Total number of ways that can be formed ABBCABBC is \[\frac{8!}{4!2!2!}=420\] |
Let ABBC be a unit, then this unit and other ABBC can be arranged in \[\frac{5!}{2!}=60\] |
But this includes two times |
\[\therefore \]Actual number = 59 |
\[\therefore \]Required number of ways \[=420-59=361\] |
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