A) \[\frac{6}{5}\]
B) \[\frac{12}{5}\]
C) \[\frac{18}{5}\]
D) \[\frac{24}{5}\]
Correct Answer: B
Solution :
We have, \[det(A)=2det(B)=3,det(C)=5\] |
\[\Rightarrow \]\[\det \,({{A}^{2}}B{{C}^{-1}})=\det (A)\times \det (A)\times \det (B)\times \frac{1}{\operatorname{detC}}\] |
\[=2\times 2\times 3\frac{1}{5}=\frac{12}{5}\] |
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