A) 4
B) 1
C) 16
D) 18
Correct Answer: C
Solution :
Given, \[abcd=1\] |
\[\frac{1+a}{2}\le \sqrt{a}\] |
\[AM\ge GM\] |
\[1+a\ge 2\sqrt{a}\] |
Similarly, \[1+b\ge 2\sqrt{b}\] |
\[1+c\ge 2\sqrt{c}\] |
\[\Rightarrow \]\[1+d\ge 2\sqrt{d}\] |
\[\therefore \]\[(1+a)(1+b)(1+c)(1+d)\ge 16\sqrt{abcd}\] |
\[(1+a)(1+b)(1+c)(1+d)\ge 16\] |
You need to login to perform this action.
You will be redirected in
3 sec