KVPY Sample Paper KVPY Stream-SX Model Paper-14

  • question_answer
    An energy of 40.8 eV is required to excite a Hydrogen-like species from 1st Bohr orbit to second. Which is/are correct statements):

    A) Atomic number of H-like species is 2.

    B) lonisation energy of H-like species is 122.4 eV.

    C) Kinetic energy of electron in 1st orbit is 50.4 eV.

    D) Energy of third orbit is \[-13.6\,\,eV.\]

    Correct Answer: A

    Solution :

    \[{{E}_{2}}-{{E}_{1}}=\Delta \,E\]
    \[40.8=13.6{{Z}^{2}}\,\,\left( \frac{1}{1}-\frac{1}{4} \right)=13.6\times \frac{3}{4}{{Z}^{2}}\]
    \[{{Z}^{2}}=4\]\[\Rightarrow \]\[Z=2\]
    \[lE=13.6{{Z}^{2}}=13.6\times {{2}^{2}}=54.4\,ev\]
    \[K{{E}_{1}}=13.6{{Z}^{2}}=13.6\times {{2}^{2}}=54.4\,ev\]


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