A) is equal to \[\frac{5}{2}\]
B) lies in the interval (1, 2)
C) is strictly greater than \[\frac{5}{2}\]
D) is strictly greater than \[\frac{3}{2}\]but less than \[\frac{5}{2}\]
Correct Answer: B
Solution :
\[\left| z \right|\ge 1\] \[\left| z+\frac{1}{2} \right|\ge \left| |z|+\left| \frac{1}{2} \right| \right|\] \[\ge \left| 2-\frac{1}{2} \right|\ge \frac{3}{2}\] Hence, minimum distance between z and \[\left( -\frac{1}{2},0 \right)\] is \[\frac{3}{2}.\]
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