KVPY Sample Paper KVPY Stream-SX Model Paper-15

  • question_answer
    Plane electromagnetic wave of frequency 50 MHz "travels in free space along the positive x direction. At a particular point in space and time, \[\vec{E}=6.3\hat{j}\] V/m. The corresponding magnetic field B, at that point will be:

    A) \[18.9\times {{10}^{-8}}\hat{k}\text{T}\]

    B) \[6.3\times {{10}^{-8}}\hat{k}\text{T}\]

    C) \[2.1\times {{10}^{-8}}\hat{k}\text{T}\]

    D) \[18.7\times {{10}^{8}}\hat{k}\text{T}\]

    Correct Answer: C

    Solution :

    \[\left| \text{B} \right|=\frac{\left| \text{E} \right|}{\text{C}}\]
    \[=\,\frac{6.3}{3\times {{10}^{8}}}=\,2.1\times {{10}^{-8}}\text{T}\]
    and       \[\text{\hat{E}}\times \text{\hat{B}}\,\text{=}\,\text{\hat{C}}\]
                \[\hat{j}\times \hat{B}=\hat{i}\]
                \[\text{\hat{B}}\,\text{=}\,\hat{k}.\]
                \[\text{\vec{B}}\,\text{=}\,\left| \text{B} \right|\text{\hat{B}=2}\text{.1}\times \text{10}{{\,}^{\text{-}\,\text{8}}}\text{\hat{K}T}\]


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