KVPY Sample Paper KVPY Stream-SX Model Paper-17

  • question_answer
    The energy associated with electric field is \[\text{(}{{\text{U}}_{\text{E}}}\text{)}\] and with magnetic field is \[\text{(}{{\text{U}}_{\text{B}}}\text{)}\] for an electromagnetic wave in free space. Then:

    A) \[{{\text{U}}_{\text{E}}}\text{=}\frac{{{\text{U}}_{\text{B}}}}{\text{2}}\]

    B) \[{{\text{U}}_{\text{E}}}\text{}{{\text{U}}_{\text{B}}}\]

    C) \[{{\text{U}}_{\text{B}}}\text{}{{\text{U}}_{\text{B}}}\]

    D) \[{{\text{U}}_{\text{E}}}\text{=}{{\text{U}}_{\text{B}}}\]

    Correct Answer: D

    Solution :

     
    \[B=\frac{E}{C}\]
    \[\Rightarrow \]   \[{{U}_{E}}=\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}\]
    \[{{U}_{B}}=\frac{{{B}^{2}}}{2{{\mu }_{0}}}=\frac{{{E}^{2}}}{2{{\mu }_{0}}{{C}^{2}}}\]
    \[=\frac{{{E}^{2}}}{2{{\mu }_{o}}}({{\mu }_{0}}{{\varepsilon }_{o}})={{U}_{E}}.\]


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