A) \[3\pm 3\sqrt{2}\]
B) \[3+2\sqrt{3}\]
C) \[3-2\sqrt{3}\]
D) \[3\pm 2\sqrt{2}\]
Correct Answer: D
Solution :
Let \[r\]be the radius of the circle. Its equation is \[{{x}^{2}}+{{y}^{2}}-2r(x+y)+{{r}^{2}}=0.\]since it passes through \[P(a,b)\] |
\[{{a}^{2}}+{{b}^{2}}-2r(a+b)+{{r}^{2}}=0\] |
Solving \[{{r}_{1}}=a+b\sqrt{2ab}\] ? (1) |
\[{{r}_{2}}=a+b-\sqrt{2ab}\] |
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