A) \[{{10}^{-\,19}}\text{/}{{\mu }_{0}}\]
B) \[{{10}^{-\,19}}{{\mu }_{0}}\]
C) \[2\times {{10}^{-\,19}}{{\mu }_{0}}\]
D) \[2\times {{10}^{-\,19}}\text{/}{{\mu }_{0}}\]
Correct Answer: B
Solution :
| He nucleus revolving in circle behave as current carrying coil of \[i=\frac{q}{T}=\frac{2e}{T}\] |
| \[{{B}_{at\,\,center}}=\frac{{{\mu }_{0}}i}{2R}=\frac{{{\mu }_{0}}}{2R}\times \frac{2e}{T}=\frac{{{\mu }_{0}}e}{TR}\] |
| \[\frac{{{\mu }_{0}}\times 1.6\times {{10}^{-19}}}{2\times 0.8}={{\mu }_{0}}\times {{10}^{-19}}\] |
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