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KVPY Sample Paper KVPY Stream-SX Model Paper-18

  • question_answer
    Total number of stereoisomers possible for this molecule are \[C{{H}_{3}}CH=CHC{{H}_{2}}CHBrC{{H}_{3}}\]

    A) 8

    B) 2

    C) 4

    D) 6

    Correct Answer: C

    Solution :

    Total number of stereoisomers = number of geometrical + number of optical isomers \[C{{H}_{3}}CH=CHC{{H}_{2}}CHBrC{{H}_{3}}\]is an alkene, so it can have two geometrical forms is and Irons. Since, the given compound has a chiral centre, therefore each geometrical isomer has a pair of enantiomer. Thus, in all there are \[2\times 2=4\] stereoisomers possible for given compound.


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