2. Sample Papers
  3. KVPY

KVPY Sample Paper KVPY Stream-SX Model Paper-18

  • question_answer
    Equivalent conductance of \[NaCl,\]\[HCl\] and \[{{C}_{2}}{{H}_{5}}COONa,\] at infinite dilution are 126.45, 426.16 and \[91\,{{\Omega }^{-\,1}}c{{m}^{2}}\] respectively. The equivalent conductance of \[{{C}_{2}}{{H}_{5}}COOH\] is

    A) \[201.28{{\Omega }^{-\,1}}c{{m}^{-\,2}}\]

    B) \[390.71{{\Omega }^{-\,1}}c{{m}^{-\,2}}\]

    C) \[698.28\,{{\Omega }^{-1}}c{{m}^{-2}}\]

    D) \[540.48{{\Omega }^{-1}}c{{m}^{-2}}\]

    Correct Answer: B

    Solution :

    Given,
    \[\lambda _{NaCl}^{\infty }=126.45\,{{\Omega }^{-1}}c{{m}^{2}}\]
    \[\lambda _{HCl}^{\infty }=426.16\,{{\Omega }^{-1}}c{{m}^{2}}\]
    \[\lambda _{{{C}_{2}}{{H}_{5}}COONa}^{\infty }=91\,{{\Omega }^{-1}}c{{m}^{2}}\]
    \[{{\lambda }_{{{C}_{2}}{{H}_{5}}COOH}}=\lambda _{{{C}_{2}}{{H}_{5}}COONa}^{\infty }+\lambda _{HCl}^{\infty }-\lambda _{NaCl}^{\infty }\]
    \[=91+4261.6-126.45\]
    \[=390.71\,{{\Omega }^{-\,1}}c{{m}^{-\,2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner