A) \[0.01M\,NaCl\]
B) \[0.005M\,{{C}_{2}}{{H}_{5}}OH\]
C) \[0.0005M\,Mg{{I}_{2}}\]
D) \[0.005\,M\,MgS{{O}_{4}}\]
Correct Answer: A
Solution :
| The depression in freezing point is a colligative property. Thus, it depends upon number of particles or ions. More is the number of ions, minimum will be the freezing point. |
| For \[0.01M\,NaCl,\] |
| Number of ions \[=0.01\times 2=0.02\] |
| For \[0.005\,M\,{{C}_{2}}{{H}_{5}}OH,\] |
| Number of ions \[0.005\times 1=0.015\] |
| For \[0.005\,M\,Mg{{I}_{2}},\] |
| Number of ions \[=0.005\times 3=0.015\] |
| For \[MgS{{O}_{4}},\] |
| Number of ions \[=0.005\times 2=0.01\] |
| As, \[0.01M\,NaCl\]has highest number of ions, so it will have minimum freezing point. |
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