A) \[n=4,l=1,m=+\,2,s=+\frac{1}{2}\]
B) \[n=4,l=0,m=0,s=+\frac{1}{2}\]
C) \[n=3,l=2,m=+\,2,s=+\frac{1}{2}\]
D) \[n=4,l=2,m=-\,1,s=+\frac{1}{2}\]
Correct Answer: B
Solution :
| Given, conditions should be followed for an electron in an orbital. |
| (i) The value of l should ranges between 0 to \[n-1.\] |
| (ii) The value of m should ranges between \[-l\] |
| \[\,to+l.\] |
| (iii) The value of \[s=+\frac{1}{2}\]or \[-\frac{1}{2}.\] |
| The electronic configuration of \[Ti\]is \[[Ar]\] |
| \[3{{d}^{2}},4{{s}^{2}}.\] |
| Therefore, \[n=4,\]\[l=0,\]\[m=0,\]\[s=+\frac{1}{2}.\] |
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