KVPY Sample Paper KVPY Stream-SX Model Paper-18

  • question_answer
    A compound forms hexagonal close-packed structure. What is the total number of voids in 0.5 mole of it?

    A) \[3.011\times {{10}^{23}}\]

    B) \[6.022\times {{10}^{23}}\]

    C) \[9.033\times {{10}^{23}}\]     

    D) \[1.802\times {{10}^{24}}\]

    Correct Answer: C

    Solution :

    Total number of voids = Number of octahedral voids + Number of tetrahedral voids.
    Number of octahedral voids = Total number of atoms (N) is a closed structure (0.5 mol)
    \[=0.5\times 6.022\times {{10}^{23}}\]\[=3.011\times {{10}^{23}}\]
    Number of tetrahedral voids = 2N \[=2\times 3.011\times {{10}^{23}}=6.022\times {{10}^{23}}\]
    Total number of voids \[=3.011\times {{10}^{23}}+6.022\times {{10}^{23}}\]\[=9.033\times {{10}^{23}}\]


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