KVPY Sample Paper KVPY Stream-SX Model Paper-18

  • question_answer
    Let \[f:\left[ \frac{1}{2},1 \right]\]\[\to \]\[R\] (the set of all real numbers) be a positive non-constant and differentiable function such that \[f\,'(x)<2f(x)\] and  \[f\,\left( \frac{1}{2} \right)=1.\]  Then, the value of \[\int\limits_{1/2}^{1}{f(x)dx}\] lies in the interval

    A) \[\left( 2e-1,\text{ }2e \right)\]

    B) \[(e-1,\,\,2e-1)\]

    C) \[\left( \frac{e-1,}{2}\,\,,\,\,e-1 \right)\]

    D) \[\left( 0\,\,,\,\,\frac{e-1}{2} \right)\]

    Correct Answer: D

    Solution :

    Given, \[f'(x)<2f(x)\]
    \[\Rightarrow \]\[\frac{f'(x)}{f(x)}<2\]
    On integrating, we get \[f(x)<C{{e}^{2x}}\]
    Put \[x=\frac{1}{2}\]\[\Rightarrow \]\[C>\frac{1}{e}\]
    Hence, \[f(x)<\frac{{{e}^{2x}}}{e}\]
    \[\Rightarrow \]\[f(x)<{{e}^{2x-1}}\]
    \[\Rightarrow \]\[0<\int\limits_{1/2}^{1}{f(x)dx<}\int\limits_{1/2}^{1}{{{e}^{2x-1}}dx}\]
    \[0<\int\limits_{1/2}^{1}{f(x)<\frac{e-1}{2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner