KVPY Sample Paper KVPY Stream-SX Model Paper-19

  • question_answer
    The freezing point of aqueous solution that contains 3% urea, 7.45% KCl and 9% of glucose is (given \[{{K}_{f}}\] of water = 1.86 and asume molarity = molality).

    A) 290 K

    B) 285.5 K

    C) 267.42 K

    D) 250 K

    Correct Answer: C

    Solution :

    \[\Delta \,{{T}_{f}}=i.m.\,\,{{K}_{f}}\]
    \[\Delta \,{{T}_{f}}={{i}_{1}}{{m}_{1}}{{K}_{f}}+{{i}_{2}}{{m}_{2}}{{K}_{f}}+{{i}_{3}}{{m}_{3}}{{K}_{f}}=({{m}_{1}}+2{{m}_{2}}+{{m}_{3}}){{K}_{f}}\]
    \[\Delta \,{{T}_{f}}=\frac{\frac{3}{60}+\frac{7.45\times 2}{74.5}+\frac{9}{180}}{100}\times 1000\times 1.86\]
    \[\Delta \,{{T}_{f}}=3\times 1.86\]\[=5.58\]
    \[{{T}_{f}}\]of solution \[=273-5.58=267.42\,\,K\]


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