A) \[-\,1\]
B) 0
C) 1
D) 2
Correct Answer: A
Solution :
\[y=\frac{{{x}^{3}}}{8}+x\cos x+cos2x\] |
\[\frac{{{x}^{3}}}{8}+x\cos x+2{{\cos }^{2}}x-1\] |
\[=2{{\left( \cos x+\frac{x}{4} \right)}^{2}}=-1.\] |
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