A) \[\frac{3}{5},\frac{2}{5}\]
B) \[\frac{2}{5},\frac{4}{15}\]
C) \[\frac{7}{15},\frac{2}{15}\]
D) \[\frac{3}{10},\frac{2}{10}\]
Correct Answer: B
Solution :
Probability of A to not win \[=1-\frac{1}{3}=\frac{2}{3}\] |
\[P(B)=\frac{2}{3}.\frac{3}{5}=\frac{2}{5}\] |
\[P(C)=\frac{2}{3}.\frac{2}{5}=\frac{4}{15}\] |
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