A) \[f\propto \frac{1}{n}\]
B) \[f\propto \frac{1}{{{n}^{2}}}\]
C) \[f\propto \frac{1}{{{n}^{3}}}\]
D) \[f\propto \frac{1}{{{n}^{3/2}}}\]
Correct Answer: C
Solution :
| \[hf=Rhc\left[ \frac{1}{{{(n-1)}^{2}}}-\frac{1}{{{n}^{2}}} \right]\] |
| Or \[f=Rc\left[ \frac{{{n}^{2}}-{{\left( n-1 \right)}^{2}}}{{{\left( n-1 \right)}^{2}}{{n}^{2}}} \right]=RC\frac{\left( 2n-1 \right)}{{{\left( n-1 \right)}^{2}}{{n}^{2}}}\] |
| For \[n>>1,\,2n-1\simeq n.\]and \[n-1\simeq n.\] |
| \[f\propto \frac{1}{{{n}^{3}}}\] |
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