A) \[2.16\,\overset{{}^\circ }{\mathop{A}}\,\]
B) \[3.62\,\overset{{}^\circ }{\mathop{A}}\,\]
C) \[3.94\overset{{}^\circ }{\mathop{A}}\,\]
D) \[4.15\,\overset{{}^\circ }{\mathop{A}}\,\]
Correct Answer: B
Solution :
\[4r=a\sqrt{2}\] \[a=\frac{4r}{\sqrt{2}}=\frac{4\times 1.28}{\sqrt{2}}\overset{{}^\circ }{\mathop{A}}\,=3.62\overset{{}^\circ }{\mathop{A}}\,\]
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