A) \[2r,\frac{4r}{\sqrt{3}},2\sqrt{2r}\]
B) \[\frac{4r}{\sqrt{3}},2\sqrt{2r},2r\]
C) \[2r,2\sqrt{2r},\frac{4r}{\sqrt{3}}\]
D) \[2\sqrt{2r},\frac{4r}{\sqrt{3}},2r\]
Correct Answer: D
Solution :
[D] \[\sec :a=2r;\]\[bcc:\sqrt{3a}=4r;\]\[fcc:\sqrt{2a}=4r;\]You need to login to perform this action.
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