A) \[-\frac{d\,[A]}{dt}=k\,{{[A]}^{2}}\]
B) \[-\frac{d\,[A]}{dt}=k\,[A]\]
C) \[-\frac{d\,[A]}{dt}=\frac{k}{4}[A]\]
D) \[-\frac{d\,[A]}{dt}=k\,{{[A]}^{1/2}}\]
Correct Answer: D
Solution :
[D]\[A\xrightarrow{{}}\,\,\operatorname{Product}\] | |
We know, Rate \[=K{{[conc.]}^{n}}\] | |
\[1\times {{10}^{-4}}=K{{[.01]}^{n}}\] | ??.. (i) |
\[1.41\times {{10}^{-4}}=K{{[.02]}^{n}}\] | ??.. (ii) |
(i)/(ii) \[\frac{1}{1.41}={{\left( \frac{1}{2} \right)}^{n}}\] | |
\[n=\frac{1}{2}\] | |
Then \[\frac{-d(A)}{dt}=K{{[A]}^{1/2}}\] |
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