A) \[\frac{1}{2}\]
B) \[\frac{1}{3}\]
C) \[\frac{2}{5}\]
D) \[\frac{1}{5}\]
Correct Answer: C
Solution :
[c]| Let event A = Each American ma- is seated adjacent to his wife. |
| B = Indian men is seated adjacent to his wife |
| Now, \[n\,(A\cap B)=4!\times {{(2!)}^{4}}\] |
| Event when each American man is seated adjacent to his wife |
| \[\therefore \] \[n\,(A)=(5!)\times {{(2!)}^{4}}\] |
| \[\Rightarrow \] \[P\left( \frac{B}{A} \right)=\frac{n\,(A\cap B)}{P\,(B)}\] |
| \[=\frac{4!\times {{(2!)}^{5}}}{5!\times {{(2!)}^{4}}}=\frac{2}{5}\] |
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