A) Increasing
B) Decreasing
C) First increases then decreases
D) First decreases and then increases
Correct Answer: B
Solution :
[B] \[{{V}_{1}}=\frac{{{v}^{2}}}{{{u}^{2}}}{{V}_{0}}\] & \[v=\frac{uf}{-\,u-\,f}\Rightarrow \frac{-\,f}{u+f}=\frac{v}{u}\] \[{{V}_{rel}}={{V}_{0}}-{{V}_{i}}=\left( 1-\frac{{{v}^{2}}}{{{u}^{2}}} \right)\,\,\,{{V}_{0}}=\left[ 1-{{\left( \frac{f}{f+u} \right)}^{2}} \right]\] \[{{V}_{0}}\]as u increase \[{{v}_{rel}}\]decreases
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