A) 1
B) 5
C) 4
D) 2
Correct Answer: C
Solution :
\[PC{{l}_{5}}+S{{O}_{2}}\xrightarrow{{}}POC{{l}_{3}}+SOC{{l}_{2}}\] |
\[PC{{l}_{5}}+{{H}_{2}}O\xrightarrow{{}}POC{{l}_{3}}+2HCl\] |
\[PC{{l}_{5}}+{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}POC{{l}_{3}}+S{{O}_{2}}Cl+2HCl\] |
\[6PC{{l}_{5}}+{{P}_{4}}{{O}_{10}}\xrightarrow{{}}10POC{{l}_{3}}\] |
Hence, there are four compounds which among the given compounds which gives \[POC{{l}_{3}}\] on reaction \[PC{{l}_{5}}\]. |
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