question_answer

If a straight line passing through the point \[P(-3,4)\] is such that its intercepted portion between the coordinate axes is bisected at P, then its equation is:

A) \[3x-4y+25=0\]

B) \[4x-3y+24=0\]

C) \[x-y+7=0\]

D) \[4x+3y=0\]

Correct Answer: B

Solution :

Let the line be \[\frac{x}{a}+\frac{y}{b}=1\]

\[(-3,4)=\left( \frac{a}{2},\frac{b}{2} \right)\]

\[a=-6,\] b = 8

Equation of line is

\[4x-3y+24=0.\]