A) Particle moves along circular path
B) Particle moves along parabolic path
C) Particle moves along elliptical path
D) Particle moves along straight line
Correct Answer: C
Solution :
| Position of particle is\[r=3\cos \omega t\,\hat{i}+4\sin \omega t\,\hat{j}\] |
| So,\[x=3\cos \omega t,y=4\sin \omega t\]we have \[\Rightarrow \]\[\frac{x}{3}=\cos \omega t,\]\[y=4\sin \omega t\] |
| So, we have \[\frac{{{x}^{2}}}{9}+\frac{{{y}^{2}}}{16}={{\cos }^{2}}\omega t+{{\sin }^{2}}\omega t\] or \[\frac{{{x}^{2}}}{9}+\frac{{{y}^{2}}}{16}=1\] |
| This is an ellipse. |
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