| A triangular lamina is given, |
 |
| Let, \[{{I}_{AB}},{{I}_{BC}}\]and \[{{I}_{AC}}\]are the moments of inertia of lamina about AB, BC and AC. |
| Now, choose the correct option. |
A) \[{{I}_{AB}}+{{I}_{BC}}={{I}_{AC}}\]
B) \[{{I}_{AC}}>{{I}_{AB}}<{{I}_{BC}}\]
C) \[{{({{I}_{AB}})}^{2}}+{{({{I}_{BC}})}^{2}}={{({{I}_{AC}})}^{2}}\]
D) \[{{I}_{AB}}>{{I}_{BC}}>{{I}_{AC}}\]
Correct Answer: D
Solution :
Moment of inertia about shortest side is maximum because effective distance of mass distribution about this side is maximum.
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