A) \[50-55%\]
B) \[9-12%\]
C) \[21-23%\]
D) \[11-12%\]
Correct Answer: C
Solution :
| \[s-\]character cc bond angle |
| For \[25%\]s character (as in \[s{{p}^{3}}\]hybrid orbital), bond angle is \[109.5{}^\circ \], for 33.3%s character (as in \[s{{p}^{2}}\]hybrid orbital), bond angle is \[120{}^\circ \]and for 50% s character (as in sp hybrid orbital), bond angle is \[180{}^\circ .\] |
| Similarly, when the bond angle decreases below \[109.5{}^\circ \], the A'-character will decrease accordingly. |
| Decreasing in angle \[=120{}^\circ -109.5{}^\circ =10.5{}^\circ \] |
| Decrease in .y-character \[=33.3\text{ }%\text{ }-25\text{ }%\] |
| \[=\text{ }8.3\text{ }%\]Actual decrease in bond angle\[=109.5{}^\circ -105{}^\circ =4.5{}^\circ \] |
| Expected decrease in,\[s-\]character\[=\frac{8.3}{10.5}\times 4.5=3.56%\] |
| Thus, the \[s-\]character should decrease by about \[3.56%\]i.e., |
| \[s-character=25-3.56-21.44%\] |
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