A) \[3.7\times {{10}^{5}}Bq\]
B) \[3.7\times {{10}^{8}}Bq\]
C) \[3.7Bq\]
D) \[3.7\times {{10}^{10}}Bq\]
Correct Answer: B
Solution :
| A 10 Gy dose of radiation corresponds to 10 J of radiation energy. As tumor mass is 0.003 kg energy for 10 Gy dose is |
| \[{{E}_{1}}=0.003\times 10=0.03J\] |
| Each disintegration provides \[0.7MeV\]\[{{H}^{+}}\] |
| To provide \[0.03J\]number of iisintegrations required is |
| \[N=\frac{0.03}{1.12\times {{10}^{-13}}}=268\times {{10}^{11}}\]decays |
| These must occurs in 14 min, |
| Number of decays per second \[=n=\frac{N}{t}\]\[=\frac{268\times {{10}^{11}}}{14\times 60}=3.7\times {{10}^{8}}\] decays \[{{s}^{-1}}\] |
| Source activity required is\[R=3.7\times {{10}^{8}}Bq\] |
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