| The major product of the following reaction is: |
| \[C{{H}_{3}}C{{H}_{2}}\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{CH}}\,-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,\underset{in\,liq\,N{{H}_{3}}}{\mathop{\xrightarrow[(ii)\,NaN{{H}_{2}}]{(i)KOH\,alc.}}}\,\] |
A) \[C{{H}_{3}}CH=C=C{{H}_{2}}\]
B) \[C{{H}_{3}}C{{H}_{2}}\underset{\underset{N{{H}_{2}}}{\mathop{|}}\,}{\mathop{CH}}\,-\underset{\underset{N{{H}_{2}}}{\mathop{|}}\,}{\mathop{CH}}\,{{ }_{2}}\]
C) \[C{{H}_{3}}CH=CHC{{H}_{2}}N{{H}_{2}}\]
D) \[C{{H}_{3}}C{{H}_{2}}C=CH\]
Correct Answer: D
Solution :
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