A) 0.40
B) 1.50
C) 1.0
D) 0.75
Correct Answer: D
Solution :
| \[2\pi r=n\lambda \] |
| \[\lambda =\frac{2\pi r}{n}=\frac{2\pi {{n}^{2}}{{a}_{0}}}{n\times Z}=2\pi \frac{n}{Z}{{a}_{0}}\] |
| \[\lambda =1.5\pi {{\alpha }_{0}}\] |
| \[\therefore \] \[2\pi \frac{n}{Z}{{a}_{0}}=1.5\pi {{\alpha }_{0}}\]\[\Rightarrow \] \[\frac{n}{Z}=\frac{1.5}{2}=0.75.\] |
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