question_answer

In the Q.26, the current \[{{I}_{1}}\] long after pressing the switch is

A) 2.5 amp

B) 2 amp

C) 5/6 amp

D) 5/3 amp

Correct Answer: A

Solution :

After long time induced emf in L become zero so, L is replaced with simple conducting wire. So new equivalent circuit is shown.

\[{{I}_{1}}=\frac{E}{{{R}_{eq}}}\]

\[{{R}_{eq}}=2+{{R}_{eq}}\] of 6 &\[3\Omega =2+\frac{6\times 3}{6+3}=2+2=4\]

\[{{I}_{1}}=\frac{10}{4}=2.5\,\,amp\]