• # question_answer During the process A-B for an ideal gas- A) Work done on the gas is zero B) Density of the gas is constant C) Slope of line AB from the T-axis is directly proportional to the number of moles of the gas D) All of the above

 P-T graph is a straight line passing through the origin. Therefore V = constant Work done on the gas, Further, density of the gas, $\rho =\frac{m}{V}$ $\therefore \rho \propto \frac{1}{V}$ Since Volume of the gas is constant, density of the gas is constant. $PV=nRT$ $p=\left( \frac{nR}{V} \right)T$ i.e., slope of P-T line is proportional to n.